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In this video I go over the linear equation of a plane, which involves rewriting and simplifying the scalar equation of a plane. I do this by starting with the scalar equation of a plane and then collecting all like terms and replacing the constants addition with a single letter "d", thus obtaining the linear equation of a plane in the form: ax + by + cz + d = 0.
I also do 2 examples on planes to illustrate this concept. The first example involves finding the equation of a plane when given 3 points on the plane. The second example involves finding the point of intersection of a line and plane, whose equations are both given. And as always, I graph out the results using the amazing GeoGebra 3D graphing calculator as a double check of my work. You can play around with the calculator via these links: https://www.geogebra.org/calculator/mm6t7n4q and https://www.geogebra.org/calculator/raqsvnad.
The timestamps of key parts of the video are listed below:
This video was taken from my earlier video listed below:
Related videos:
Vectors and the Geometry of Space video series: https://www.youtube.com/playlist?list=PLai3U8-WIK0FjJpwnxwdrOR7L8Ul8VZoZ .
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