Mathematical Problems on Knitting (Part 03) in Bengali

Today i have discussed some mathematical problems ok Knitting of Textile Processing again.
নিটিং এ যারা জব করেন বা ফেব্রিক ম্যানুফেকচারিং এর ছাত্র তাদের জন্য নিটিং (Knitting) এর গানিতিক সমস্যাগুলো অনেক গুরুত্বপূর্ন। আমরা জানি, নিটিং এর মূল কাজ সেটিং পয়েন্ট ও ক্যাল্কুলেশন সংক্রান্ত। তাই আমি ধারাবাহিকভাবে Knitting এর যাবতীয় গানিতিক সমস্যাগুলো আলোচনা করেছি। আশা করি এই ম্যাথগুলো মনোযোগ দিয়ে দেখার পর আপনার Knitting Calculation and Mathematics এ আর তেমন কোন সমস্যা থাকবে না।

আজকে তৃতীয় পর্বে সাধারন কিছু গানিতিক সমস্যা নিয়ে আলোচনা করেছি।
আজকের আলোচিত ম্যাথগুলোঃ

1. Calculate Production in m/hr, Fabric Width and Production in Kg/hr of a S/J circular knitting machine having following parameters
   Machine dia = 30”, Gauge = 28 Yarn Count = Nm 50/1 (Ne 29.6/1)
   Number of Feeder = 96 Course Density = 18 courses/cm
   Machine Speed = 35 rpm Wales Density = 13 wales/cm
   Machine Efficiency = 85% Fabric Weight = 125 gm/m2
   [95.2 m/hr, 2.03 m, 24.157 kg/hr]
2. Calculate the length in fabric in yards of a plain single jersey fabric knitted at 34 cpi on a 30” dia, 24 gauge circular knitting machine having 96 feeders. The machine is running for 24 hours at 27 rpm and the efficiency is 90%.

1. A circular S/J weft knitting machine having 20 feeders, running at a speed of 25 rpm, is knitting fabric with stitch length equal to 0.15” with 756 needles in the machine. The efficiency of the machine is 84% and the count of cotton yarn knitted is 18S. The fabric is knitted with 24 cpi. Calculate the production in yards and pound per hour [29 yards, 5.25 lb]

1. Calculate the length in m of a plain, S/J fabric knitted at 16 cpcm on a 26 inch dia 28G circular m/c having 104 feeds. The m/c operates for 8 hours at 29 rpm at 95% efficiency. [859.6 m]

1. Calculate Machine Performance in meter and kg, and fabric width from following parameters of circular knitting machine
   Machine dia = 30” Structure: Plain Interlock
   Gauge = 28 Yarn: Polyester dtex 76/1
   Number of Feeder = 96 Course Density = 17 courses/cm
   Machine Speed = 31 rpm Wales Density = 14 wales/cm
   Machine Efficiency = 85% Fabric Weight = 100 gm/m2
   [44.64 m/hr, 8.39 kg/hr, 1.88 m]

1. Calculate Machine Performance in meter and kg, and fabric width from following parameters of circular knitting machine
   Machine dia = 30” Structure: Three Colour Jacquard
   Gauge = 20 Yarn: Polyester dtex 150/1
   Number of Feeder = 96 Course Density = 12 courses/cm
   Machine Speed = 23 rpm Wales Density = 11 wales/cm
   Machine Efficiency = 80% Fabric Weight = 180 gm/m2

1. Calculate the production in m/shift of a D/J (Interlock) circular knitting machine from the following data
   Machine dia = 30” Machine rpm = 30
   Gauge = 24 Efficiency = 94%
   Number of Feeder = 96 Shift = 12 hours

1. Calculate the length in fabric in yards of a 1×1 interlock knitted at 34 courses per inch on a 30” dia, 24 G circular, having 96 feeders. The machine is running for 24 hours at 27 rpm and efficiency is 90%.

1. Calculate the length of fabric produced per shift at 75% efficiency of a knitting machine from the following particulars
   No. of Feeders = 48 Fabric open width = 264 cm
   Stitch density = 15 (per sq. cm) Machine Speed = 20 rpm
   Machine Diameter = 30” Machine Gauge = 14
   [1152 m]

1. Calculate the courses/cm of a fabric producing 1152 metres per 8 hours shift in a circular knitting machine with 48 feeder and 20 rpm [Efficiency = 75%] [3]

1. Calculate the total no. of wales/day of a 30” dia, 28 G, 90 feeder circular S/J machine. Assume rpm is 30

1. Calculate the production in Kg of 8 hours of a s/j circular knitting machine from the parameters-
   Machine dia = 30” Machine rpm = 40
   Gauge = 28 Loop Length = 2 mm
   Number of Feeder = 90 Yarn Count = 30 s
   Efficiency = 90%
   Also Calculate knitting Speed, wales per day and courses per day